Hi civil engineers today I will share some
useful calculations . this calculations are fundamental for civil engineers.
therefore this calculations are used most of the times to calculate various
materials like cement and sand volume in mortar ,brick volume in brick word,
cement ,sand and aggregate in concrete, volume of steel in reinforced cement
concrete.
QUANTITY OF CEMENT ,FINE AGGREGATE, COARSE AGGREGATE REQUIRED FOR DIFFERENT GRADES OF CEMENT CONCRETE FOR ONE CUBIC METRE.
GRADE OF CONCRETE
|
RATIO
|
CEMENT BAGS
|
FINE AGGREGATE (SAND )
M3
|
COARSE AGGREGATE
20 mm
M3
|
COARSE AGGREGATE
40 mm
M3
|
M7.5
|
1:4:8
|
3.40
|
0.48
|
-
|
0.96
|
M10
|
1:3:6
|
4.40
|
0.46
|
0.92
|
-
|
M15
|
1:2:4
|
6.30
|
0.44
|
0.88
|
-
|
M20
|
1:1.5:3
|
8.05
|
0.42
|
0.84
|
-
|
NOTE: ONE BAG CEMENT =
50 KG OR 0.034 CUB METRE
|
|||||
DRIVE HOW IT IS CALCULATED
for one m concrete for the ratio 1:2:4
Quantity of cement is one part
Quantity of sand is two parts
Quantity of coarse aggregate is four parts
total 1+2+4 = 7 unit
VOLUME OF CEMENT
Volume of cement = 1/7 x 1.5
=0.214 m3
= 0.214 x
1440 (note for unit weight of
cement ( 1m cement ) = 1440 kg / m)
= 308.16
kg
=
308.16/50
= 6.30 bags
VOLUME OF SAND
Volume of sand = (2/7) x 1.5
= 0.428 m3
Volume of coarse aggregate
Volume of coarse aggregate = (4/7 ) x 1.5 =
0.857 m3
QUANTITY OF CEMENT ,SAND ( FINE AGGREGATE )
, COARSE AGGREGATE AND BRICKS REQUIRED FOR DIFFERENT RATIO OF MORTAR IN ONE
CUBIC METRE OF BRICK WORK.
MORTAR RATIO
|
CEMENT BAGS
|
SAND
(m3)
|
BRICKS ( nos )
|
1:2
|
3.45
|
0.24
|
500
|
1:3
|
2.40
|
0.25
|
500
|
1:4
|
1.75
|
0.25
|
500
|
1:5
|
1.49
|
0.26
|
500
|
1:6
|
1.20
|
0.25
|
500
|
1:7
|
1.00
|
0.25
|
500
|
DERIVE HOW IT IS CALCULATED
To find no of bricks in one cub.metre
Size of brick = 19 cm x 9 cm x 9 cm
Mortar thick = 1 cm
Volume of one brick without mortar = 0.19 x
0.09 x 0.09
= 0.00154 m3
So size of brick with mortar thick = 20 cm
x 10 cm x 10 cm
Now volume of one brick = 0.3 x 0.1 x0.1
=
0.002 m3
No of brick in one cub metre = 1 / 0.002
= 500 nos
TO FIND VOLUME OF MORTAR ( CEMENT ,SAND, )
REQUIRED FOR ONE CUBIC METRE
Volume covered by bricks in one cubic metre
without mortar = volume of one brick x no of brick
= 0.00154 x 500
= 0.76 m3
Volume of mortar = total volume – volume of
bricks ( 500 nos )
=
1 – 0.76
=
0.24m3 ( wet volume )
Now we are take mortar ratio is 1:5
Total unit = 1+5 = 6
Volume of cement = (1x0.24 x 1.3 )/ 6
= 0.052 m3
= 0.052 x
1440
= 74.88 kg
=78.44/ 50
= 1.49 bags
Volume of sand = (5 x 0.24 x 1.3 ) / 6
= 0.26 m3
BREAK UP COST OF BUILDING
1.earth work excavation and filling = 1 % total cost
2.foundation concrete = 5 % total cost
3.damp proof course = 1% total cost
4.brick work =
34 % total cost
5. flooring = 16 % total cost
6. roofing
= 20 % total cost
7. joinery =
16 % total cost
8 plastering =
10 % total cost
9. white washing ,colour washing and
painting = 2 % total cost
10 .miscellaneous = 5 % total cost
PERCENTAGE OF REINFORCEMENT
Lintel and beam = 1 %
to 2.0 %
Column = 1 % to 5.0 %
Foundation =
0.5 % to 0.8 %
Roof slab = 0.7 % to 0.8 %
BINDING WIRE CALCULATION
Binding wire of ting wire is used to tie-up
reinforcements. Gauge of binding wire 14 to 16 gauge or 2 mm dia. Binding wire is calculated based on total
volume of reinforcement . usually 1 kg
to 1.3 kg per quintal ( 100 kg ) of
taken as reinforcement.
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