HOW TO APPROXIMATELY CALCULATE QUANTITY OF STEEL BARS IN BEAMS, COLUMNS AND SLAB WITHOUT BAR BENDING SCHEDULE

HOW TO APPROXIMATELY CALCULATE QUANTITY OF STEEL BARS IN BEAMS, COLUMNS AND SLAB WITHOUT BAR BENDING SCHEDULE



Bar bending schedule is requires to find the exact  quantity of steel for estimation of rate
But we don’t have the bar bending schedule and design data at the site
At the time we take approximate percentage value from the similar constructed project

APPROXIMATE PERCENTAGE OF STEEL IN RCC  ELEMENTS

1 lintel and beams        =1 % to 2 %
2.columns                      =1 %  to 5 %
3 foundation                  =0-.5 % to 0.8 %
4.roof slab                      =0.7 % to 0.8 %

EXAMPLE 1

Calculation of steel bars in beams

Size of beam
Length     = 5m
Breadth   =0.3 m
Depth      =0.45 m
Volume of beam  =5 x 0.3x 0.45
                               =0.675 m3  
Approximate percentage of steel in beam  =2 %
So volume of steel      =(2/100)x0.675
                                      =0.0135 m3
Unit weight of steel   =7850 kg/m3
                                     =0.135 x 7850
                                     =106 kg

EXAMPLE 2

Calculation of steel in column

Size of column
       Height h           =3 m
Lateral dimension = 0.3m x0.3 m
                                 =0.27 m
Percentage of steel in column   =1 % to 5 %
We take 3 % of steel in column
So,                  volume of steel =(3/100) x 0.27
                                                    =0.0081 m3
Unit weight steel         =7850 kg/m3
Weight of steel            =0.0081 x 7850
                                        =63.58 kg

EXAMPLE 3

Calculation of steel in roof slab

Size of roof
     Length L =3m
   Breadth B =3m
      Depth d =0.1 m
Volume of stab =L x B x D
                           =3x 0.3x0.1
                           =0.09
Volume of steel in slab=0.7 % to 0.8 %
We take 0.8 % steel in concrete
Volume of steel       =(0.8/100)x 0.09
                                   =0.00072
Unit weight of steel =7850 kg /m3
                                    =0.00072 x 7850
                                    =5.652 kg
Quantity of steel in slab = 5.652 kg



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